tan x = $-\frac{5}{12}$ gives cot x = $\frac{-12}{5}$ $\sec^2$ x = 1 + $\tan^2$ x ⇒ $\sec^2$ x = 1 + $\frac{25}{144}$ = $\frac{169}{144}$ ⇒ sec x = ± $\frac{13}{12}$ ⇒ sec x = - $\frac{13}{12}$ [since x lies in second quadrant] sec x = $-\frac{13}{12}$ gives cos x = $\frac{-12}{13}$ , sin x = tan x × cos x ⇒ sin x = $\left(-\frac{5}{12}\right)$ × $\left(\frac{-12}{13}\right)$ = $\frac{5}{13}$ , sin x = $\frac{5}{13}$ gives cosec x = $\frac{13}{5}$