The given equation of lines are 4x + 7y – 3 = 0 ... (i) and 2x – 3y + 1 = 0 ... (ii) On solving (i) and (ii), we get x = $\frac{1}{13}$ , y = $\frac{5}{13}$ Thus the lines (i) and (ii) meets at $\left(\frac{1}{13},\frac{5}{13}\right)$ Hence the equation of the line passing through $\left(\frac{1}{13},\frac{5}{13}\right)$ and has equal intercepts on the axes is $\frac{1}{13a} + \frac{5}{13a}$ = 1 [Since a = b] ⇒ $\frac{6}{13a}$ = 1 ⇒ 6 = 13a ⇒ a = $\frac{6}{13}$. ∴ The required equation of line is 13(x + y) = 6.