We have, $\frac{x}{4}+\frac{y}{6}$ = 1 ... (i) Now slope of (i) = $-\frac{3}{2}$ slope of any line perpendicular to line (i) meets the y-axis at (0, 6) is $\frac{2}{3}$. ∴ Equation of the line through (0, 6) and perpendicular to line (i) is (y - 6) = $\frac{2}{3}$ (x - 0) ⇒ 3y = - 18 = 2x ⇒ 2x - 3y + 18 = 0.