Given, the perpendicular from the origin to the line y = mx + c meets it at the point (–1, 2) ∴ 2 = m (–1) + c ... (i) ⇒ c – m = 2 Slope of the perpendicular OR = $\frac{2-0}{-1-0}$ = - 2 ... (ii) Slope of the line y = mx + c is m ⇒ m = $\frac{1}{2}$ (from (ii)) Put the value of m in (i), we get c − $\frac{1}{2}$ = 2 ⇒ c = 2 + $\frac{1}{2}$ = $\frac{5}{2}$.