(i) We have given an equation x + 7y = 0, which can be written in the form ⇒ 7y = - x ⇒ y = $\frac{-1}{7}$ x + 0 ... (1) Also, the slope intercept form is y = mx + c ... (2) On comparing (1) and (2), we get m = $\frac{-1}{7}$ , c = 0 Hence the slope is $\frac{-1}{7}$ and the y-intercept = 0. (ii) We have given an equation 6x + 3y – 5 = 0, which can be written in the form 3y = – 6x + 5 ⇒ y = − 2x + $\frac{5}{3}$ ... (1) Also, the slope intercept form is y = mx + c ... (2) On comparing (1) and (2), we get m = − 2 and c = $\frac{5}{3}$ i.e. slope = – 2 and the y-intercept = $\frac{5}{3}$ (iii) We have given an equation y = 0 ⇒ y = 0.x + 0 ... (1) Also, the slope intercept form is y = mx + c ... (2) On comparing (1) and (2), we get m = 0, c = 0. Hence, slope is 0 and the y-intercept is 0.