Let the intercepts made by the line on the x-axis and y-axis be a and 9 – a respectively. Then its equation is $\frac{x}{a}+\frac{y}{9-a}$ = 1 Since it passes through point (2, 2), we have $\frac{2}{a}+\frac{2}{9-a}$ = 1 ⇒ 2(9 – a) + 2a = a(9 – a) ⇒ 18 – 2a + 2a = 9a – $a^2$ ⇒ 18 = 9a – $a^2$ ⇒ $a^2$ – 9a + 18 = 0 ⇒ $a^2$ – 6a – 3a + 18 = 0 ⇒ a(a – 6) – 3 (a – 6) = 0 ⇒ a = 3, 6 Now, if a = 3 ⇒ b = 9 – 3 = 6 and if a = 6 ⇒ b = 9 – 6 = 3 So, required equation is $\frac{x}{3}+\frac{y}{6}$ = 1 or $\frac{x}{6}+\frac{y}{3}$ = 1 i.e., 2x + y – 6 = 0 or x + 2y – 6 = 0.