Let the given points be A(–1, 1) and B(2, –4). We know that the equation of a line passing through the given points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\frac{y-y_1}{x-x_1}$ = $\frac{y_2-y_1}{x_2-x_1}$ Here, $x_1$ = – 1, $y_1$ = 1, $x_2$ = 2, $y_2$ = – 4 So, the equation of a line passing through the given points is $\frac{y-1}{x-(-1)}$ = $\frac{-4-1}{2-(-1)}$ ⇒ $\frac{y-1}{x+1}$ = $\frac{-5}{3}$ ⇒ 3 (y - 1) = - 5 (x + 1) ⇒ 5x + 3y + 2 = 0 Hence, the required equation is 5x + 3y + 2 = 0.