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NCERT Class XI Mathematics - Statistics - Solutions

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Question : 8 of 34
Marks: +1, -0
xix_i 15 21 27 30 35
fif_i 3 5 6 7 8
Solution:  
xix_i fif_i c.f. xi7\left|x_i-7\right| fixi7f_i\left|x_i-7\right|
15 3 3 15 45
21 5 8 9 18
27 6 14 3 18
30 7 21 0 0
35 8 29 5 40
29 148
Here, N2\frac{N}{2} = 292\frac{29}{2} = 14.5
The c.f. just greater than 14.5 is 21 and the corresponding value of x is 30.
So, Median (M) = 30
∴ M.D. about median = 1Ni=1nfixiM\frac{1}{N}\sum\limits_{i=1}^{n}f_i\left|x_i-M\right| = 129\frac{1}{29} × 148 = 5.1
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