36, 72, 46, 42, 60, 45, 53, 46, 51, 49

NCERT Class XI Mathematics - Statistics - Solutions

Question : 4 of 34

Marks: +1, -0

Solution:

Arranging the data in ascending order,

we have 36, 42, 45, 46, 46, 49, 51, 53, 60, 72

Here n = 10 (which is even)

So median is the average of 5th and 6th observations

Median (M) =

\frac{46+49}{2}

\frac{95}{2}

= 47.5

$x_i$	36	42	45	46	46	49	51	53	60	72	Total
$\left\|x_i- 47.5\right\|$	11.5	5.5	2.5	1.5	1.5	1.5	3.5	5.5	12.5	24.5	70

∴ M.D. about median =

\frac{1}{n}\sum\limits_{i=1}^{n}\left|x_i-M\right|

\frac{1}{10}

× 70 = 7

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