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NCERT Class XI Mathematics - Statistics - Solutions

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Question : 12 of 34
Marks: +1, -0
Calculate the mean deviation about median age for the age distribution of 100 persons given below :
Age 16 – 20 21 – 25 26 – 30 31 – 35 36 – 40 41 – 45 46 – 50 51 – 55
Number 5 6 12 14 26 12 16 9
[Hint : Convert the given data into continuous frequency distribution by subtracting 0.5 from lower limit and adding 0.5 to the upper limit of each class interval]
Solution:  
Age Modified class Mid values
xix_i
fif_i c.f. xi38\left|x_i - 38\right| fixi38f_i\left|x_i-38\right|
16 - 20 15.5-20.5 18 5 5 20 100
21 - 25 20.5 - 25.5 23 6 11 15 90
26 - 30 25.5 - 30.5 28 12 23 10 120
31 - 35 30.5 - 35.5 33 14 37 5 70
36 - 40 35.5 - 40.5 38 26 63 0 0
41 - 45 40.5 - 45.5 43 12 75 5 60
46 - 50 45.5-50.5 48 16 91 10 160
51 - 55 50.5 - 55.5 53 9 100 15 135
100 735
Here, N2\frac{N}{2} = 1002\frac{100}{2} = 50
∴ Median class is 35.5 - 40.5
Median(M) = 35.5 + 503726\frac{50-37}{26} × 5 = 35.5 + 2.5 = 38
Mean deviation about median = 1Nni=1fixiM\frac{1}{N}\sum^{\underset{i=1}{n}} f_i\left|x_i-M\right| = 735100\frac{735}{100} = 7.35
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