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NCERT Class XI Mathematics - Statistics - Solutions

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Question : 11 of 34
Marks: +1, -0
Find the mean deviation about median for the following data :
Marks0 - 10 10 – 2020 – 30 30 – 4040 – 50 50 – 60
Number of girls 6 8 1416 4 2
Solution:  
Marks Mid values
xix_i
fif_i c.f. xi27.86\left|x_i-27.86\right| fixi27.86f_i\left|x_i-27.86\right|
0 - 10 5 6 6 22.86 137.16
10 - 20 15 8 14 12.86 102.88
20 - 30 25 14 28 2.86 40.04
30 - 40 35 16 44 7.14 114.24
40 - 50 45 4 48 17.14 68.56
50 - 60 55 2 50 27.14 54.28
50 517.16
Here, N2\frac{N}{2} = 502\frac{50}{2} = 25
∴ Median class is 20 – 30
Median(M) = 20 + 251414\frac{25-14}{14} × 10 = 20 + 7.86 = 27.86
∴ M.D. about median = 1Nni=1fixiM\frac{1}{N}\sum\limits^{\underset{i=1}{n}} f_i\left|x_i-M\right| = 150\frac{1}{50} × 517.16 = 10.34
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