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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 8 of 106
Marks: +1, -0
ana_n = n22n;a7\frac{n^2}{2^n} ; a_7
Solution:  
We have, ana_n = n22n;a7\frac{n^2}{2^n} ; a_7
Put n = 7 , a7a_7 = (7)227\frac{(7)^2}{2^7} = 49128\frac{49}{128}
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