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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 7 of 106
Marks: +1, -0
ana_n = 4n−3,a17,a244n-3,a_{17},a_{24}
Solution:  
We have, ana_n = 4n−3,a17,a244n-3,a_{17},a_{24}
Put n = 17 ⇒ a17a_{17} = 4(17) – 3 = 68 – 3 = 65
put n = 24 ⇒ a24a_{24} = 4 (24) – 3 = 96 – 3 = 93.
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