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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 56 of 106
Marks: +1, -0
If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that aqrbrpcpqa^{q–r} b^{r–p} c^{p–q} = 1.
Solution:  
Let A be the first term and R be the common ratio, then according to question
ARp1AR^{p – 1} = a, ARq1AR^{q – 1} = b, ARr1AR^{r – 1} = c
aqrbrpcpqa^{q – r} b^{r – p} c^{p – q} = (ARp1)(qr)(ARq1)(rp)(ARr1)(pq)(AR^{p – 1})^(q – r) (AR^{q – 1})^(r – p) (AR^{r – 1})^(p – q)
= A(qr)+(rp)+(pq)A^{(q – r) + (r – p) + (p – q)} R(p1)(qr)+(q1)(rp)+(r1)(pq)R^{(p – 1) (q – r) + (q – 1) (r – p) + (r – 1) (p – q)} = A0R0A^0 R^0 = 1 ⋅ 1 = 1
Hence, aqrbrpcpqa^{q – r} b^{r – p} c^{p – q} = 1.
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