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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 44 of 106
Marks: +1, -0
x3,x5,x7x^3, x^5, x^7 , ... n terms (if x ≠ ±1).
Solution:  
In the given G.P., a = x3x^3, r = x2x^2 and SnS_n = a[1−rn]1−r\frac{a[1-r^n]}{1-r} , if |r| < 1
∴ SnS_n = x3[1−(x2)n]1−x2\frac{x^3 [1-(x^2)^n]}{1-x^2} = x3[1−x2n]1−x2\frac{x^3[1-x^{2n}]}{1-x^2}
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