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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 43 of 106
Marks: +1, -0
1, – a, a2a^2, – a3a^3 , ... n terms (if a ≠ – 1).
Solution:  
In the given G.P., a = 1, r = – a and SnS_n = a[1rn]1r\frac{a[1-r^n]}{1-r} , if |r| < 1
SnS_n = [1(a)n]1+a\frac{[1-(-a)^n]}{1+a}
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