Test Index

NCERT Class XI Mathematics - Sequences and Series - Solutions

© examsnet.com
Question : 3 of 106
Marks: +1, -0
ana_n = 2n2^n
Solution:  
We have, ana_n = 2n2^n
Substituting n = 1, 2, 3, 4, 5, we get
a1a_1 = 212^1 = 2; a2a^2 = 222^2 = 4; a3a^3 = 232^3 = 8; a4a^4 = 242^4 = 16;
a5a_5 = 252^5 = 32.
∴ The first five terms are 2, 4, 8, 16, 32.
© examsnet.com
Go to Question: