Test Index

NCERT Class XI Mathematics - Sequences and Series - Solutions

© examsnet.com
Question : 2 of 106
Marks: +1, -0
ana_n = nn+1\frac{n}{n+1}
Solution:  
We have, ana_n = nn+1\frac{n}{n+1}
Substituting n = 1, 2, 3, 4, 5, we get
a1a_1 = 11+1\frac{1}{1+1} = 12\frac{1}{2} , a2a_2 = 22+1\frac{2}{2+1} = 23\frac{2}{3},
a3a_3 = 33+1\frac{3}{3+1} = 34\frac{3}{4} , a4a_4 = 44+1\frac{4}{4+1} = 45\frac{4}{5} , a5a_5 = 55+1\frac{5}{5+1} = 56\frac{5}{6}
∴ The first five terms are 12,23,34,45,56\frac{1}{2},\frac{2}{3},\frac{3}{4},\frac{4}{5},\frac{5}{6}.
© examsnet.com
Go to Question:
Prev Question
Next Question