Test Index

NCERT Class XI Mathematics - Probability - Solutions

© examsnet.com
Question : 26 of 54
Marks: +1, -0
A die is thrown, find the probability of following events:
(i) A prime number will appear;
(ii) A number greater than or equal to 3 will appear;
(iii) A number less than or equal to one will appear;
(iv) A number more than 6 will appear;
(v) A number less than 6 will appear.
Solution:  
An experiment consists of throwing a die.
∴ The sample space of the experiment is given by S = {1, 2, 3, 4, 5, 6}
(i) Let E be the event that a prime number will appear. E = {2, 3, 5}
∴ P (E) = n(E)n(S)\frac{n(E)}{n(S)} = 36\frac{3}{6} = 12\frac{1}{2}
(ii) Let F be the event that a number ≥ 3 will appear. F = {3, 4, 5, 6}
∴ P (F) = n(F)n(S)\frac{n(F)}{n(S)} = 46\frac{4}{6} = 23\frac{2}{3}
(iii) Let G be the event that a number ≤ 1 will appear. G = {1}
∴ P (G) = n(G)n(S)\frac{n(G)}{n(S)} = 16\frac{1}{6}
(iv) Let H be the event that a number more than 6 will appear. H = Ï•
∴ P (H) = n(H)n(S)\frac{n(H)}{n(S)} = 06\frac{0}{6} = 0
(v) Let I be the event that a number less than 6 will appear. I = {1, 2, 3, 4, 5}
∴ P (I) = n(I)n(S)\frac{n(I)}{n(S)} = 56\frac{5}{6}
© examsnet.com
Go to Question: