Total no. of vowels in English = 5 Total no. of consonants in English = 21 No. of words with two different vowels & 2 different consonants formed = $\,{}^{5}C_2 \times \,{}^{21}C_2$ = $\frac{5!}{3!2!} \times \frac{21!}{2!19!}$ = $\frac{5 \times 4}{2} \times \frac{21 \times 20}{2}$ = 2100 2 vowels & 2 consonants can be arranged in 4! ways. So the required no. of words = 4! × 2100 = 24 × 2100 = 50400.