7 ≤ $\frac{3x+11}{2}$ ≤ 11 Multiplying each side by 2, we get 7 × 2 ≤ $\frac{3x+11}{2}$ × 2 ≤ 11 × 2 or 14 ≤ 3x + 11 ≤ 22 Subtracting 11, we get 14 – 11 ≤ 3x + 11 – 11 ≤ 22 – 11 or 3 ≤ 3x ≤ 11 Dividing by 3, 1 ≤ x ≤ $\frac{11}{3}$ i.e., x is greater than or equal to 1 and less than or equal to $\frac{11}{3}$ or x ∊ $\left[1,\frac{11}{3}\right]$