- 12 < 4 - $\frac{3x}{-5}$ ≤ 2 Subtracting 4 from each side, we get - 12 - 4 < 4 - $\frac{3x}{-5}$ - 4 ≤ 2 - 4 ⇒ - 16 < $\frac{3x}{5}$ ≤ - 2 Multiplying each side by 5/3, we get - 16 × $\frac{5}{3}$ < $\frac{3x}{5}$× $\frac{5}{3}$ ≤ - 2× $\frac{5}{3}$ ⇒ - $\frac{80}{3}$ < x ≤ $\frac{-10}{3}$ or x ∊ $\left(\frac{-80}{3},\frac{-10}{3}\right)$