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NCERT Class XI Mathematics - Introduction to Three Dimensional Geometry - Solutions

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Question : 11 of 20
Marks: +1, -0
Given that P(3, 2, –4), Q(5, 4, –6) and R(9, 8, –10) are collinear. Find the ratio in which Q divides PR.
Solution:  
Let Q(5, 4, –6) divides the line segment joining the points P(3, 2, –4) and R(9, 8, –10) in the ratio k : 1 internally.
∴ Then coordinates of Q are
(9k+3k+1,8k+2k+1,10k4k+1)\left( \frac{9k+3}{k+1} , \frac{8k+2}{k+1} , \frac{-10k-4}{k+1} \right)
But it is given that coordinates of Q are (5, 4, –6)
9k+3k+1\frac{9k+3}{k+1} = 5 ⇒ 9k + 3 = 5k + 5 ⇒ 4k = 2 ⇒ k = 12\frac{1}{2}
Thus Q divides the line segment joining the points P and R in the ratio 12\frac{1}{2} : 1 i.e., 1 : 2
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