NCERT Class XI Mathematics - Conic Sections - Solutions

© examsnet.com
Question : 58
Total: 71
Foci (0, ±13), the conjugate axis is of length 24.
Solution:  
Here foci are (0, ±13) which lie on y-axis.
So the equation of hyperbola in standard form is
y2
a2
x2
b2
= 1.
Now, foci are (0, ±13) ⇒ c = 13
Length of conjugate axis is 2b = 24 ⇒ b = 12
We know that c2 = a2+b2
(13)2 = a2+(12)2a2 = 169 – 144 = 25
Thus required equation of parabola is
y2
25
x2
144
= 1.
© examsnet.com
Go to Question: