Here foci are (0, ±13) which lie on y-axis. So the equation of hyperbola in standard form is $\frac{y^2}{a^2} - \frac{x^2}{b^2}$ = 1. Now, foci are (0, ±13) ⇒ c = 13 Length of conjugate axis is 2b = 24 ⇒ b = 12 We know that $c^2$ = $a^2 + b^2$ ⇒ $(13)^2$ = $a^2 + (12)^2$ ⇒ $a^2$ = 169 – 144 = 25 Thus required equation of parabola is $\frac{y^2}{25} - \frac{x^2}{144}$ = 1.