Since the major axis is along the x-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2}+\frac{y^2}{b^2}$ = 1 Since the ellipse passes through point (4, 3) ∴ $\frac{16}{a^2}+\frac{9}{b^2}$ = 1 ... (i) Also, the ellipse passes through point (6, 2) ∴ $\frac{36}{a^2}+\frac{4}{b^2}$ = 1 ... (ii) Solving (i) and (ii), we get $a^2$ = 52 and $b^2$ = 13 Hence the required equation of ellipse is $\frac{x^2}{52}+\frac{y^2}{13}$ = 1.