Since the major axis is along y-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2}+\frac{y^2}{b^2}$ = 1 Since the ellipse passes through the point (3, 2) ∴ $\frac{9}{b^2}+\frac{4}{a^2}$ = 1 ... (i) Also, the ellipse passes through point (1, 6) ∴ $\frac{1}{b^2}+\frac{36}{a^2}$ = 1 ... (ii) Solving (i) and (ii), we get $a^2$ = 40 and $b^2$ = 10 Hence the required equation of ellipse is $\frac{x^2}{10}+\frac{y^2}{40}$ = 1.