Clearly, the foci (±4, 0) lie on x-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2}+\frac{y^2}{b^2}$ = 1 Now vertices are (±5, 0) ⇒ a = 5, foci are (±4, 0) ⇒ c = 4 Also, we know that $c^2$ = $a^2 - b^2$ ∴ $(4)^2$ = $(5)^2 - b^2$ ⇒ $b^2$ = 25 – 16 = 9. Hence the required equation of ellipse is $\frac{x^2}{25}+\frac{y^2}{9}$ = 1