Given equation of ellipse is $4x^2 + 9y^2$ = 36 i.e., $\frac{\frac{4x^2}{9y^2}}{36}$ = 1 ⇒ $\frac{x^2}{9} + \frac{y^2}{4}$ = 1 Clearly, 9 > 4 ⇒ $a^2$ = 9 and $b^2$ = 4 The equation of ellipse in standard form is $\frac{x^2}{a^2} + \frac{y^2}{b^2}$ = 1 ∴ $a^2$ = 9 ⇒ a = 3 and $b^2$ = 4 ⇒ b = 2 We know that c = $\sqrt{a^2 - b^2}$ ⇒ c = $\sqrt{9-4}$ = $\sqrt{5}$ ∴ Coordinates of foci are (±c, 0) i.e. (± $\sqrt{5}$, 0) Coordinates of vertices are (±a, 0) i.e. (±3, 0). Length of major axis = 2a = 2 × 3 = 6 Length of minor axis = 2b = 2 × 2 = 4 Eccentricity (e) = $\frac{c}{a}$ = $\frac{\sqrt{5}}{3}$ Length of latus rectum = $\frac{2b^2}{a}$ = $\frac{2 \times 4}{3}$ = $\frac{8}{3}$