Here h = $\frac{1}{2}$ , k = $\frac{1}{4}$ and r = $\frac{1}{12}$ The equation of circle is, $(x - h)^2 + (y - k)^2$ = $r^2$ ∴ $\left(x+\frac{1}{2}\right)^2+\left(y-\frac{1}{4}\right)^2$ = $\left(\frac{1}{12}\right)^2$ ⇒ $x^2 + \frac{1}{4} - x + y^2 + \frac{1}{16} - \frac{1}{2} y$ = $\frac{1}{144}$ ⇒ $144x^2$ + 36 – 144x + $144y^2$ + 9 – 72y = 1 ⇒ $144x^2 + 144y^2$ – 144x – 72y + 44 = 0 ⇒ 4($36x^2 + 36y^2$ – 36x – 18y + 11) = 0 ⇒ $36x^2 + 36y^2$ – 36x – 18y + 11 = 0