The given equation of parabola is $y^2$ = 10x, which is of the form $y^2$ = 4ax. ∴ 4a = 10 ⇒ a = $\frac{10}{4}$ ⇒ a = $\frac{5}{2}$ ∴ Coordinates of focus are $\left(\frac{5}{2},0\right)$ Axis of parabola is y = 0 Equation of the directrix is x = $-\frac{5}{2}$ ⇒ 2x + 5 = 0 Length of latus rectum = $\frac{4 \times 5}{2}$ = 10.