NCERT Class XI Chemistry Thermodynamics Solutions

Question : 4 of 22

Marks: +1, -0

ΔU° of combustion of methane is – X

kJ mol^{–1}

. The value of ΔH° is

Solution:

CH_{4(g)} + 2O_{2(g)}

→

CO_{2(g)} + 2H_2O_(l)

Δn = 1 - 3 = - 2.

ΔH° = ΔU° + ΔnRT = - X - 2RT

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