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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 36 of 67
Marks: +1, -0
2 × 10810^{8} atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.
Solution:  
An atom will cover length equal to its diameter.
Diameter of carbon atom = 2.42×108\frac{2.4}{2 \times 10^{8}} = 1.2 × 10−810^{-8} cm
Radius of carbon atom = 1.2×10−82\frac{1.2 \times 10^{-8}}{2} = 0.6 × 10−810^{-8} cm = 0.6 × 10−8×10−210^{-8} \times 10^{-2} m
= 0.06 × 10−910^{-9} m = 0.06 nm
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