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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 35 of 67
Marks: +1, -0
If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.
Solution:  
A carbon atom covers length = diameter of atom = 0.15 nm
= 0.15 × 10−910^{-9} × 102 cm = 0.15 × 10−710^{-7} cm
∴ Number of carbon atoms which can be placed on 20 cm length
= 200.15×10−7\frac{20}{0.15 \times 10^{-7}} = 1.33 × 10910^9
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