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NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

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Question : 5 of 36
Marks: +1, -0
Calculate the mass of sodium acetate (CH3COONa)\mathrm{(CH_3COONa)} required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol−1\mathrm{g\ mol}^{-1}.
Solution:  
Molar mass of sodium acetate = 82.0245 g mol−1\mathrm{g\ mol}^{-1}
Mass of CH3COONa\mathrm{CH_3COONa} required to make 500 mL of 0.375 M solution
= 0.375×82.0245×5001000\frac{0.375 \times 82.0245 \times 500}{1000} = 15.38 g
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