ICSE Class X Math 2016 Solved Paper

Question : 1

Total: 57

SECTION - I

Using remainder theorem, find the value of k if on dividing 2x3+3x2−kx+5 by x−2, leaves a remainder 7.

Solution:

Let f(x)=2x3+3x2−kx+5
By remainder theorem, when f(x) is divided by (x−2),
x−2=0,⇒x=2
‌ the remainder ‌‌=f(2)
‌=2(2)3+3(2)2−k(2)+5
‌=16+12−2k+5
‌=33−2k
According to question
33−2k‌=7
2k‌=26
k‌=13

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