ICSE Class X Math 2016 Solved Paper

© examsnet.com
Question : 2
Total: 57
Given A=[
20
−17
]
and I=[
10
01
]
and A2= 9A+mI. Find m.
Solution:  
Given :
A=[
20
−17
]
and I=[
10
01
]

‌A2=A⋅A=[
20
−17
]
[
20
−17
]

‌‌=[
40
−2−70+49
]

‌‌=[
40
−949
]

‌9A+mI=9[
20
−17
]
+m[
10
01
]

=[
180
−963
]
+[
m0
0m
]

‌‌=[
18+m0
−963+m
]

Now, According to question,
A2‌=9A+mI
[
40
−949
]
‌
=[
18+m0
−963+m
]

comparing both sides,
4‌=18+m‌ and ‌49=63+m
⇒ m‌=−14
© examsnet.com
Go to Question: