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ICSE Class X Math 2016 Paper

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Question : 12 of 57
Marks: +1, -0
If (3a+2b):(5a+3b)=18:29(3 a+2 b):(5 a+3 b)=18: 29 . Find a:ba: b .
Solution:  
    Given:   (3a+2b):(5a+3b)=18:29\;\,\text{ Given: }\;(3 a+2 b):(5 a+3 b)=18: 29
  ⇒    3a+2b5a+3b=1829\; \Rightarrow \; \; \frac{3 a+2 b}{5 a+3 b} = \frac{18}{29}
  ⇒    87a+58b=90a+54b\; \Rightarrow \; \; 87 a+58 b=90 a+54 b
  ⇒    3a=4b\; \Rightarrow \; \; 3 a=4 b
  ab=43\; \frac{a}{b} = \frac{4}{3}
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