ICSE Class X Math 2016 Paper

In the given figure below, $A D$ is a diameter. $O$ is the centre of the circle. $A D$ is parallel to $B C$ and $\angle C B D=32^{\circ}$ . Find:

Question : 11 of 57

Marks: +1, -0

\angle BED

Solution:

\triangle ABD

\angle ABD = \; 90^{\circ}

\; (\; \text{ angle in a semicircle} ) \;

\angle ADB = \; 32^{\circ}

\angle BAD = \; 180-(90+32)

= \; 58^{\circ} .

\angle BAD = \; \angle BED

(angle in the same segment)

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