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ICSE Class X Math 2015 Paper

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In the given figure ABCA B C is a triangle and BCB C is parallel to the yy-axis. ABA B and ACA C intersects the yy-axis at PP and QQ respectively.
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Question : 26 of 52
Marks: +1, -0
Find the ratio in which QQ divides A  CA\;C.
Solution:  
Let the ratio be k:1k: 1
\therefore Coordinates of PP is
(m1x2+m2x1m1+m2,  m1y2+m2y1m1+m2)\left( \frac{m_1 x_2 + m_2 x_1}{m_1+m_2}, \; \frac{m_1 y_2 + m_2 y_1}{m_1+m_2} \right) =(2k+yk+1,  4kk+1)= \left( \frac{-2k+y}{k+1}, \; \frac{-4k}{k+1} \right)
Let coordinates of PP is (x,y)(x, y) .
x=2k+4k+1x = \frac{-2k+4}{k+1}
0=2k+4k+1[as P lies on y-axis]0 = \frac{-2k+4}{k+1} \qquad \text{[as P lies on } y \text{-axis]}
2k=4k=22k = 4 \Rightarrow k=2
Ratio=2:1\text{Ratio} = 2:1
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