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ICSE Class X Math 2015 Paper

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In the given figure ABCA B C is a triangle and BCB C is parallel to the yy-axis. ABA B and ACA C intersects the yy-axis at PP and QQ respectively.
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Question : 25 of 52
Marks: +1, -0
Find the length of ABA B and ACA C .
Solution:  
Coordinates of A(4,0)A(4,0) and B(2,3)B(-2,3)
   Length of   AB  =(24)2+(30)2\; \text{ Length of } \; A B \; = \sqrt{(-2-4)^2+(3-0)^2}
  =36+9=45\; = \sqrt{36+9} = \sqrt{45}
  =35   units.   \; = 3 \sqrt{5} \; \text{ units. } \;
Coordinates of A(4,0)A(4,0) and C(2,4)C(-2,-4)
   Length of   AC  =(24)2+(40)2\; \text{ Length of } \; A C \; = \sqrt{(-2-4)^2+(-4-0)^2}
  =36+16=52\; = \sqrt{36+16} = \sqrt{52}
  =213   units.   \; = 2 \sqrt{13} \; \text{ units. } \;
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