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ICSE Class X Math 2013 Paper

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Question : 32 of 46
Marks: +1, -0
Find xx and yy if (x3xy4y)(21)=(512)\begin{pmatrix} x & 3x \\ y & 4y \end{pmatrix}\begin{pmatrix} 2 \\ 1 \end{pmatrix}=\begin{pmatrix} 5 \\ 12 \end{pmatrix}
Solution:  
Given : (x3xy4y)(21)  =(512)\begin{pmatrix} x & 3x \\ y & 4y \end{pmatrix}\begin{pmatrix} 2 \\ 1 \end{pmatrix}\;=\begin{pmatrix} 5 \\ 12 \end{pmatrix}
(2x+3x2y+4y)  =(512)\begin{pmatrix} 2x+3x \\ 2y+4y \end{pmatrix}\;=\begin{pmatrix} 5 \\ 12 \end{pmatrix}
(5x6y)  =(512)\begin{pmatrix} 5x \\ 6y \end{pmatrix}\;=\begin{pmatrix} 5 \\ 12 \end{pmatrix}
∴5x=5\therefore 5x=5
⇒x=1\Rightarrow x=1
and 6y=126y=12
⇒y=2\Rightarrow y=2
Hence, x=1x=1 and y=2y=2
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