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ICSE Class 10 Physics 2020 Paper

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SECTION - II
The figure below shows a simple pendulum of mass 200 g200\ \mathrm{g}. It is displaced from the mean position A to the extreme position B. The potential energy at the position AA is zero. At the position BB the pendulum bob is raised by 5 m5\ \mathrm{m}.
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Question : 28 of 67
Marks: +1, -0
What is the total mechanical energy at point CC ?
Solution:  
Total mechanical energy at point CC == Total mechanical energy of point BB
=U+K= U + K
  =10+0\;=10+0 (K=0,∵V=0)(K=0, \because V=0)
  =10J.\;=10 J .
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