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ICSE Class 10 Physics 2020 Paper

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SECTION - II
The figure below shows a simple pendulum of mass 200 g200\ \mathrm{g}. It is displaced from the mean position A to the extreme position B. The potential energy at the position AA is zero. At the position BB the pendulum bob is raised by 5 m5\ \mathrm{m}.
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Question : 27 of 67
Marks: +1, -0
What is the potential energy of the pendulum at the position BB ?
Solution:  
At the position BB,
U  =mghU\;=m g h
  =  2001000×10×5\;=\;\frac{200}{1000} \times 10 \times 5 (m=200  g=  2001000  kg)\left(\because m=200 \; g=\;\frac{200}{1000} \; \mathrm{kg}\right)
  =10J\;=10 \mathrm{J}
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