ICSE Class 10 Physics 2018 Paper

A half metre rod is pivoted at the centre with two weights of $20\,\mathrm{gf}$ and $12\,\mathrm{gf}$ suspended at a perpendicular distance of $6\,\mathrm{cm}$ and $10\,\mathrm{cm}$ from the pivot respectively as shown below.

Question : 41 of 78

Marks: +1, -0

Is the rod in equilibrium?

Solution:

Clockwise moment of force

=12 \text{gf} \times 10 \text{cm}

=120 \text{gf} - \text{cm}

Anticlockwise moment of force

=20 \text{gf} \times 6 \text{cm}

=120 \text{gf} - \text{cm}

since, the clockwise moment of force is equal to the anticlockwise moment of force, the rod is in equilibrium

Thus, Yes, the rod is in equilibrium.

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