ICSE Class 10 Physics 2018 Paper

You have three resistors of values $2 Ω, 3 Ω$ and $5 Ω$ . How will you join them so that the total resistance is more than $7 Ω$ ?

Question : 22 of 78

Marks: +1, -0

Draw a diagram for the arrangement.

Solution:

The three resistors are

2 Ω, 3 Ω

and

5 Ω

. If we join them in series, the total resistance will become

2+3+5=10 Ω

which is more than

7 Ω

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