ICSE Class 10 Chemistry 2023 Solved Paper
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Question : 74
Total: 88
The percentage of phosphorus in the fertilizer super phosphate Ca ( H 2 PO 4 ) 2 H = 1 P = 31 , O = 16 , C a = 40 ]
Solution:
Molecular mass of Ca ( H 2 PO 4 ) 2
= 40 + ( 1 × 2 + 31 + 16 × 4 ) × 2
= 234 amu .
Percentage of Phosphorous
=
=
× 100 = 26.49 %
Percentage of Phosphorous
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