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ICSE Class 10 Chemistry 2016 Paper

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A gas cylinder contains 12×102412 \times 10^{24} molecules of oxygen gas.
If Avogadro's number is 6×10236 \times 10^{23}; Calculate :
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Question : 61 of 85
Marks: +1, -0
the volume of oxygen at S.T.P. present in the cylinder. [O=16][O=16]
Solution:  
Volume of molecule
  =     No. of molecules   NA\;=\;\frac{\;\text{ No. of molecules }\;}{N_A} ×   Molar Volume   \times \;\text{ Molar Volume }\;
  =  12×10246×1023×22.4\;=\;\frac{12 \times 10^{24}}{6 \times 10^{23} \times 22.4}
  =  2×10×22.4\;=\;2 \times 10 \times 22.4
  =  448   litres.   \;=\;448 \;\text{ litres. }\;
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