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ICSE Class 10 Chemistry 2016 Paper

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A gas cylinder contains 12×102412 \times 10^{24} molecules of oxygen gas.
If Avogadro's number is 6×10236 \times 10^{23}; Calculate :
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Question : 60 of 85
Marks: +1, -0
the mass of oxygen present in the cylinder.
Solution:  
Let Mass of molecule
= No. of Molecules NA= \frac{\text{ No. of Molecules }}{N_A} × Molecular Mass \times \text{ Molecular Mass }
=12×12246×1023×(2×16)= \frac{12 \times 12^{24}}{6 \times 10^{23}} \times (2 \times 16)
=2×10×32=640 g= 2 \times 10 \times 32 = 640 \text{ g}
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