In Young's double slit experiment, the ...

CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

Question : 9 of 13

Marks: +1, -0

In Young's double slit experiment, the separation between the two slits in

d

and distance of the screen from the slits is

1000 d

. If the first minima falls at a distance

d

from the central maximum, obtain the relation between

d

and

\lambda

Solution: 👈: Video Solution

Position of

n^{\;\text{th }\;}

dark fringe from the centre is

y_n = (2n-1) \;\frac{\lambda D}{d}

For

1^{\;\text{st }\;}

minima,

y_1 \;=\; \frac{\lambda D}{2d}

or,

d \;=\; \frac{\lambda \times 1000 d}{2 d}

\therefore \;\; d=500 \lambda

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